Skip to main content
Logo image

A First Course in Complex Analysis

Exercises 5.4 Exercises

1.

Compute the following integrals, where \(\Box\) is the boundary of the square with vertices at \(\pm4\pm4i\text{,}\) positively oriented:

(a)

\(\ds \int_\Box\frac{\exp(z^2)}{z^3}\diff{z}\)
Answer.
\(2 \pi i\)

(b)

\(\ds \int_\Box\frac{\exp(3z)}{(z-\pi i)^2}\diff{z}\)
Answer.
\(-6 \pi i\)

(c)

\(\ds \int_\Box\frac{\sin(2z)}{(z-\pi)^2}\diff{z}\)
Answer.
\(4 \pi i\)

(d)

\(\ds \int_\Box\frac{\exp(z)\cos(z)}{(z-\pi)^3}\diff{z}\)
Answer.
\(0\)

2.

Prove the formula for \(f''\) in Theorem 5.1.1.
Hint.
Modify the proof of the integral formula for \(f'(w)\) as follows:
  1. Write a difference quotient for \(f''(w)\text{,}\) and use the formula for \(f'(w)\) in Theorem 5.1.1 to convert this difference quotient into an integral of \(f(z)\) divided by some polynomial.
  2. Subtract the desired integral formula for \(f''(w)\) from your integral for the difference quotient, and simplify to get the analogue of (5.1).
  3. Find a bound as in the proof of Theorem 5.1.1 for the integrand, and conclude that the limit of the difference quotient is the desired integral formula.

3.

Integrate the following functions over the circle \(C[0,3]\text{:}\)

(e)

\(\ds \left( \frac{ \cos z }{ z } \right)^2\)
Answer.
\(0\)

(g)

\(\ds \frac{ \sin z }{ (z^2 + \frac 1 2)^2 }\)

(h)

\(\ds \frac{ 1 }{ (z+4) ( z^2 + 1 ) }\)

(i)

\(\ds \frac{\exp(2z)}{(z-1)^2(z-2)}\)

4.

Compute \(\ds \int_{ C[0,2] } \frac{ \exp z }{ (z-w)^2 } \, \diff{z}\) where \(w\) is any fixed complex number with \(|w| \ne 2\text{.}\)
Answer.
\(2 \pi i \exp(w)\)

5.

Define \(f : D[0,1] \to \C\) through
\begin{equation*} f(z) \ := \ \int_{ [0,1] } \frac{ \diff{w} }{ 1-wz } \end{equation*}
(the integration path is from 0 to 1 along the real line). Prove that \(f\) is holomorphic in the unit disk \(D[0,1]\text{.}\)

6.

To appreciate Corollary 5.1.6, show that the function \(f: \R \to \R\) given by
\begin{equation*} f(x) \ := \ \begin{cases}x^2 \sin(\frac 1 x) \amp \text{ if } x \ne 0 \, , \\ 0 \amp \text{ if } x = 0 \end{cases} \end{equation*}
is differentiable in \(\R\text{,}\) yet \(f'\) is not even continuous (much less differentiable) at 0.

7.

Prove that \(f(z) = {\overline z}^2\) does not have an antiderivative in any nonempty region.

8.

Show that \(\exp ( \sin z )\) has an antiderivative on \(\C\text{.}\) (What is it?)

9.

Find a region on which \(f(z) = \exp( \frac 1 z)\) has an antiderivative. (Your region should be as large as you can make it. How does this compare with the real function \(f(x) = e^{\frac 1 x}\text{?}\))

10.

Suppose \(f\) is continuous on \(\C\) and \(\lim_{z \to \infty} f(z)\) is finite. Show that \(f\) is bounded.
Hint.
If \(\lim_{z\to \infty} f(z) = L\text{,}\) use the definition of the limit at infinity to show that there is \(R>0\) so that \(\abs{f(z)-L} \lt 1\) if \(\abs z >R\text{.}\)
Now argue that \(|f(z)| \lt |L|+1\) for \(|z| > R\text{.}\) Use an argument from calculus to show that \(|f(z)|\) is bounded for \(\abs z\le R\text{.}\)

11.

Let \(p\) be a polynomial of degree \(n>0\text{.}\) Prove that there exist complex numbers \(c, z_1, z_2, \dots, z_k\) and positive integers \(j_1, \dots , j_k\) such that
\begin{equation*} p(z) \ = \ c \left( z - z_1 \right)^{j_1} \left( z - z_2 \right)^{j_2} \cdots \left( z - z_k \right)^{j_k} \, \text{,} \end{equation*}
where \(j_1 + \dots + j_k = n\text{.}\)

13.

Suppose \(f\) is entire and \(|f(z)| \le \sqrt{ |z| }\) for all \(z \in \C\text{.}\) Prove that \(f\) is identically 0.
Hint.
Show first that \(f\) is constant.

14.

Suppose \(f\) is entire and there exists \(M > 0\) such that \(|f(z)| \ge M\) for all \(z \in \C\text{.}\) Prove that \(f\) is constant.

15.

Suppose \(f\) is entire with bounded real part, i.e., writing \(f(z) = u(z) + i \, v(z)\text{,}\) there exists \(M > 0\) such that \(|u(z)| \le M\) for all \(z \in \C\text{.}\) Prove that \(f\) is constant.
Hint.
Consider the function \(\exp(f(z))\text{.}\)

16.

Suppose \(f\) is entire and there exist constants \(a\) and \(b\) such that \(|f(z)| \leq a|z| + b\) for all \(z \in \C\text{.}\) Prove that \(f\) is a polynomial of degree at most 1.

17.

Suppose \(f: D[0,1] \to D[0,1]\) is holomorphic. Prove that for \(|z| \lt 1\text{,}\)
\begin{equation*} \left| f'(z) \right| \le \frac{ 1 }{ (1 - |z|)^2 } \,\text{.} \end{equation*}

18.

Compute \(\ds \int_{ -\infty }^\infty \frac{ \diff{x} }{ x^4 + 1 } \text{.}\)
Answer.
\(\frac{ \pi }{ \sqrt 2 }\)

19.

In this problem \(f(z) = \frac{ \exp(iz) }{z^2+1}\) and \(R>1\text{.}\) Modify our computations in Example 5.3.5 as follows.

(a)

Show that \(\int_{\sigma_R}f = \frac \pi e\) where \(\sigma_R\) is again (as in Figure 5.3.6) the counterclockwise semicircle formed by the segment \([-R,R]\) on the real axis, followed by the circular arc \(\gg_R\) of radius \(R\) in the upper half plane from \(R\) to \(-R\text{.}\)

(b)

Show that \(\abs{\exp(iz)}\le1\) for \(z\) in the upper half plane, and conclude that \(\abs{f(z)}\le \frac 2 {\abs{z}^2}\) for sufficiently large \(|z|\text{.}\)

(c)

Show that \(\lim_{R\to\infty}\int_{\gg_R} f = 0\) and hence \(\lim_{R\to\infty}\int_{[-R,R]} f = \frac \pi e\text{.}\)

(d)

Conclude, by just considering the real part, that
\begin{equation*} \int_{-\infty}^\infty \frac{\cos(x)}{x^2+1}\,\diff{x} \ = \ \frac \pi e \, \text{.} \end{equation*}

20.

Compute \(\ds \int_{-\infty}^\infty \frac{\cos(x)}{x^4+1}\,\diff{x} \text{.}\)
Answer.
\(\displaystyle \frac{\pi}{e^{1/\sqrt{2}}} \sin\left(\frac{1}{\sqrt{2}} + \frac{\pi}{4}\right)\)

21.

This exercise outlines how to extend some of the results of this chapter to the Riemann sphere as defined in Section 3.2. Suppose \(G \subseteq \C\) is a region that contains 0, let \(f\) be a continuous function on \(G\text{,}\) and let \(\gg \subset G \setminus \{0\}\) be a piecewise smooth path in \(G\) avoiding the origin, parametrized as \(\gg(t)\text{,}\) \(a \le t \le b\text{.}\)

(a)

Show that
\begin{equation} \int_\gg f(z) \,\diff{z} \ = \ \int_\sigma f\!\left(\frac{1}{z}\right) \frac{1}{z^2} \, \diff{z} \tag{5.2} \end{equation}
where \(\sigma(t) := \frac{ 1 }{ \gg(t) }\text{,}\) \(a \le t \le b\text{.}\)

(b)

Now suppose \(\gg\) is closed and \(\lim_{ z \to 0 } f\!\left(\frac{1}{z}\right) \frac{1}{z^2} = L\) is finite. Let \(H := \left\{ \frac 1 z : \, z \in G \setminus \{ 0 \} \right\}\) and define the function \(g: H \cup \{ 0 \} \to \C\) by
\begin{equation*} g(z) \ := \ \begin{cases}f\!\left(\frac{1}{z}\right) \frac{1}{z^2} \amp \text{ if } z \in H, \\ L \amp \text{ if } z=0. \end{cases} \end{equation*}
Thus \(g\) is continuous on \(H \cup \{ 0 \}\) and (5.2) gives the identity
\begin{equation*} \int_\gg f \ = \ \int_\sigma g \,\text{.} \end{equation*}
In particular, we can transfer certain properties between these two integrals. For example, if \(\int_\sigma g\) is path independent, so is \(\int_\gg f\text{.}\) Here is but one application:
  1. Show that \(\int_\gg z^n \, \diff{z}\) is path independent for any integer \(n \ne -1\text{.}\)
  2. Conclude (once more) that \(\int_\gg z^n \, \diff{z} = 0\) for any integer \(n \ne -1\text{.}\)