Section 3.2 Infinity and the Cross Ratio
In the context of Möbius transformations, it is useful to introduce a formal way of saying that a function
\(f\) “blows up” in absolute value, and this gives rise to a notion of infinity.
Definition 3.2.1.
Suppose \(f: G \to \C\text{.}\)
-
\(\lim_{z\to z_0}f(z)=\infty\) means that for every
\(M>0\) we can find
\(\delta>0\) so that, for all
\(z\in G\) satisfying
\(0\lt \abs{z-z_0}\lt
\delta\text{,}\) we have
\(\abs{f(z)}>M\text{.}\)
-
\(\lim_{z\to \infty}f(z)=L\) means that for every
\(\epsilon>0\) we can find
\(N>0\) so that, for all
\(z\in G\) satisfying
\(\abs{z}>N\text{,}\) we have
\(\abs{f(z)-L}\lt \epsilon\text{.}\)
-
\(\lim_{z\to \infty}f(z)=\infty\) means that for every
\(M>0\) we can find
\(N>0\) so that, for all
\(z\in G\) satisfying
\(\abs{z}>N\text{,}\) we have
\(\abs{f(z)}>M\text{.}\)
In the first definition we require that
\(z_0\) be an accumulation point of
\(G\) while in the second and third we require that
\(\infty\) be an
extended accumulation point of
\(G\text{,}\) in the sense that for every
\(B>0\) there is some
\(z\in
G\) with
\(\abs z>B\text{.}\)
As in
Section 2.1, the limit, in any of these senses, is unique if it exists.
Example 3.2.2.
We claim that \(\lim_{ z \to 0 } \frac 1 { z^2 } =
\infty\text{:}\) Given \(M > 0\text{,}\) let \(\delta := \frac 1 { \sqrt M }\text{.}\) Then \(0 \lt |z| \lt \delta\) implies
\begin{equation*}
|f(z)| \ = \ \left| \frac 1 { z^2 } \right| \ > \ \frac 1 {
\delta^2 } \ = \ M \, \text{.}
\end{equation*}
Example 3.2.3.
Let
\(f(z) = \frac{ az+b }{ cz+d }\) be a Möbius transformation with
\(c \ne 0\text{.}\) Then
\(\lim_{ z \to \infty } f(z) = \frac a c\text{.}\)
To simplify the notation, introduce the constant
\(L := |ad
-bc|\text{.}\) Given
\(\epsilon > 0\text{,}\) let
\(N := \frac L { |c|^2 \epsilon } + \left| \frac d c
\right|\text{.}\) Then
\(|z| > N\) implies, with the reverse triangle inequality (
Corollary 1.3.5(
b)), that
\begin{equation*}
|cz+d| \ \ge \ \bigl| |c||z| - |d| \bigr| \ \ge \ |c||z| -
|d| \ > \ \frac L { |c| \epsilon }
\end{equation*}
and so
\begin{equation*}
\left| f(z) - \frac a c \right| \ = \ \left| \frac{ c(az+b) -
a(cz+d) }{ c(cz+d) } \right| \ = \ \frac L { |c| \, |cz+d| } \
\lt \ \epsilon \, \text{.}
\end{equation*}
We stress that
\(\infty\) is not a number in
\(\C\text{,}\) just as
\(\pm \infty\) are not numbers in
\(\R\text{.}\) However, we can
extend \(\C\) by adding on
\(\infty\text{,}\) if we are careful. We do so by realizing that we are always talking about a limit when handling
\(\infty\text{.}\) It turns out (see
Exercise 3.6.11) that the usual limit rules behave well when we mix complex numbers and
\(\infty\text{.}\) For example, if
\(\lim_{z\to z_0}f(z)=\infty\) and
\(\lim_{z\to z_0}g(z)=a\) is finite then the usual
limit of sum = sum of limits rule still holds and gives
\(\lim_{z\to
z_0}(f(z)+g(z))=\infty\text{.}\) The following definition captures the philosophy of this paragraph.
Definition 3.2.4.
The extended complex plane is the set \(\Chat := \C\cup\listset\infty\text{,}\) together with the following algebraic properties: For any \(a
\in \C\text{,}\)
-
\(\displaystyle \infty+a = a+\infty=\infty\)
-
if
\(a \neq 0\) then
\(\infty\cdot a = a\cdot\infty
= \infty\)
-
\(\displaystyle \infty\cdot\infty =\infty\)
-
\(\displaystyle \frac a \infty = 0\)
-
if
\(a \neq 0\) then
\(\frac a 0 = \infty \text{.}\)
The extended complex plane is also called the
Riemann sphere or the
complex projective line, denoted
\(\mathbb{CP}^1\text{.}\)
If a calculation involving
\(\infty\) is not covered by the rules above then we must investigate the limit more carefully. For example, it may seem strange that
\(\infty+\infty\) is not defined, but if we take the limit of
\(z+(-z)=0\) as
\(z\to\infty\) we will get
\(0\text{,}\) even though the individual limits of
\(z\) and
\(-z\) are both
\(\infty\text{.}\)
Now we reconsider Möbius transformations with
\(\infty\) in mind. For example,
\(f(z)= \frac 1 z\) is now defined for
\(z=0\) and
\(z=\infty\text{,}\) with
\(f(0)=\infty\) and
\(f(\infty)=0\text{,}\) and so we might argue the proper domain for
\(f(z)\) is actually
\(\Chat\text{.}\) Let’s consider the other basic types of Möbius transformations. A translation
\(f(z)
= z+b\) is now defined for
\(z=\infty\text{,}\) with
\(f(\infty) =
\infty+b = \infty\text{,}\) and a dilation
\(f(z) = az\) (with
\(a\ne0\)) is also defined for
\(z=\infty\text{,}\) with
\(f(\infty) = a\cdot\infty=\infty\text{.}\) Since every Möbius transformation can be expressed as a composition of translations, dilations and inversions (
Proposition 3.1.4), we see that every Möbius transformation may be interpreted as a transformation of
\(\Chat\) onto
\(\Chat\text{.}\) This general case is summarized in the following extension of
Proposition 3.1.2.
Corollary 3.2.5.
Suppose \(ad-bc \ne 0\) and \(c \ne 0\text{,}\) and consider \(f: \Chat \to \Chat\) defined through
\begin{equation*}
f(z) := \begin{cases}\frac{az+b}{cz+d} \amp \text{ if } z
\in \C \setminus \left\{ - \frac d c \right\} , \\ \infty
\amp \text{ if } z = - \frac d c \, , \\ \frac a c \amp
\text{ if } z = \infty \, . \end{cases}
\end{equation*}
Then \(f\) is a bijection.
This corollary also holds for
\(c = 0\) if we then define
\(f(\infty) = \infty\text{.}\)
Example 3.2.6.
Continuing
Example 3.1.3 and
Example 3.1.6, consider once more the Möbius transformation
\(f(z) = \frac{ z-1 }{ iz+i }\text{.}\) With the definitions
\(f(-1) = \infty\) and
\(f(\infty) =
-i\text{,}\) we can extend
\(f\) to a function
\(\Chat \to
\Chat\text{.}\)
With
\(\infty\) on our mind we can also add some insight to
Theorem 3.1.5. We recall that in
Example 3.1.6, we proved that
\(f(z) = \frac{ z-1 }{ iz+i }\) maps the unit circle to the real line. Essentially the same proof shows that, more generally, any circle passing through
\(-1\) gets mapped to a line (see
Exercise 3.6.4). The original domain of
\(f\) was
\(\C \setminus \{ -1 \}\text{,}\) so the point
\(z = -1\) must be excluded from these circles. However, by thinking of
\(f\) as function from
\(\Chat\) to
\(\Chat\text{,}\) we can put
\(z = -1\) back into the picture, and so
\(f\) transforms circles that pass through
\(-1\) to straight lines
plus \(\infty\text{.}\) If we remember that
\(\infty\) corresponds to being arbitrarily far away from any point in
\(\C\text{,}\) we can visualize a line plus
\(\infty\) as a circle passing through
\(\infty\text{.}\) If we make this a definition, then
Theorem 3.1.5 can be expressed as:
any Möbius transformation of \(\Chat\) transforms circles to circles.
We can take this remark a step further, based on the idea that three distinct points in
\(\Chat\) determine a unique circle passing through them: If the three points are in
\(\C\) and nonlinear, this fact comes straight from Euclidean geometry; if the three points are on a straight line or if one of the points is
\(\infty\text{,}\) then the circle is a straight line plus
\(\infty\text{.}\)
Example 3.2.7.
The Möbius transformation \(f: \Chat \to \Chat\) given by \(f(z) = \frac{ z-1 }{ iz+i }\) maps
\begin{equation*}
1 \mapsto 0 \, , \qquad \qquad i \mapsto 1 \, , \qquad
\text{ and } \qquad -1 \mapsto \infty \, \text{.}
\end{equation*}
The points
\(1\text{,}\) \(i\text{,}\) and
\(-1\) uniquely determine the unit circle and the points 0, 1, and
\(\infty\) uniquely determine the real line, viewed as a circle in
\(\Chat\text{.}\) Thus
Corollary 3.2.5 implies that
\(f\) maps the unit circle to
\(\R\text{,}\) which we already concluded in
Example 3.1.6.
Conversely, if we know where three distinct points in
\(\Chat\) are transformed by a Möbius transformation then we should be able to figure out everything about the transformation. There is a computational device that makes this easier to see.
Definition 3.2.8.
If \(z\text{,}\) \(z_1\text{,}\) \(z_2\text{,}\) and \(z_3\) are any four points in \(\Chat\) with \(z_1\text{,}\) \(z_2\text{,}\) and \(z_3\) distinct, then their cross ratio is defined as
\begin{equation*}
[z,z_1,z_2,z_3] \ := \ \frac{(z-z_1)(z_2-z_3)}{(z-z_3)(z_2-z_1)} \,\text{.}
\end{equation*}
This includes the implicit definitions \([z_3,z_1,z_2,z_3] =
\infty\) and, if one of \(z\text{,}\) \(z_1\text{,}\) \(z_2\text{,}\) or \(z_3\) is \(\infty\text{,}\) then the two terms containing \(\infty\) are canceled; e.g., \([z,\infty, z_2, z_3] = \frac{ z_2 - z_3 }{ z - z_3 }\text{.}\)
Example 3.2.9.
Our running example
\(f(z) = \frac{ z-1 }{ iz+i }\) can be written as
\(f(z) = [z,1,i,-1]\text{.}\)
Proposition 3.2.10.
The function \(f: \Chat \to \Chat\) defined by \(f(z)=[z,z_1,z_2,z_3]\) is a Möbius transformation that satisfies
\begin{equation*}
f(z_1) = 0 \, ,\qquad f(z_2) = 1 \, ,\qquad f(z_3)= \infty \,\text{.}
\end{equation*}
Moreover, if \(g\) is any Möbius transformation with \(g(z_1) = 0\text{,}\) \(g(z_2) = 1\text{,}\) and \(g(z_3)=
\infty\text{,}\) then \(f\) and \(g\) are identical.
Proof.
Most of this follows from our definition of
\(\infty\text{,}\) but we need to prove the uniqueness statement. By
Proposition 3.1.2, the inverse
\(f^{-1}\) is a Möbius transformation and, by
Exercise 3.6.10, the composition
\(h := g\circ f^{-1}\) is again a Möbius transformation. Note that
\(h(0) = g(f^{-1}(0)) = g(z_1) = 0\) and, similarly,
\(h(1) = 1\) and
\(h(\infty) = \infty\text{.}\) If we write
\(h(z)=\frac{az+b}{cz+d}\) then
\begin{align*}
0 \ = \ h(0) \ = \ \frac bd \amp \implies b=0\\
\infty \ = \ h(\infty) \ = \ \frac ac \amp \implies
c=0\\
1 \ = \ h(1) \ = \ \frac{a+b}{c+d} \ = \ \frac {a+0}{0+d} \ = \
\frac ad \amp \implies a=d
\end{align*}
and so
\begin{equation*}
h(z)\ = \\frac{az+b}{cz+d} \ = \ \frac{az+0}{0+d} \ = \ \frac ad \, z
\ = \ z \, \text{,}
\end{equation*}
the identity function. But since \(h = g\circ f^{-1}\text{,}\) this means that \(f\) and \(g\) are identical.
So if we want to map three given points of
\(\Chat\) to
\(0\text{,}\) \(1\) and
\(\infty\) by a Möbius transformation, then the cross ratio gives us the only way to do it. What if we have three points
\(z_1\text{,}\) \(z_2\) and
\(z_3\) and we want to map them to three other points
\(w_1\text{,}\) \(w_2\) and
\(w_3\text{?}\)
Corollary 3.2.11.
Suppose
\(z_1\text{,}\) \(z_2\) and
\(z_3\) are distinct points in
\(\Chat\) and
\(w_1\text{,}\) \(w_2\) and
\(w_3\) are distinct points in
\(\Chat\text{.}\) Then there is a unique Möbius transformation
\(h\) satisfying
\(h(z_1)=w_1\text{,}\) \(h(z_2)=w_2\text{,}\) and
\(h(z_3)=w_3\text{.}\)
Proof.
Let
\(h=g^{-1}\circ f\) where
\(f(z)=[z,z_1,z_2,z_3]\) and
\(g(w)=[w,w_1,w_2,w_3]\text{.}\) Uniqueness follows as in the proof of
Proposition 3.2.10.
This theorem gives an explicit way to determine
\(h\) from the points
\(z_j\) and
\(w_j\) but, in practice, it is often easier to determine
\(h\) directly from the conditions
\(f(z_j)=w_j\) (by solving for
\(a\text{,}\) \(b\text{,}\) \(c\) and
\(d\)).